Q. If the length of rod $A$ is $(3.25\ \pm 0.01)\ cm$ and that of $B$ is $(4.19\ \pm 0.01)\ cm,$ then the rod $B$ is longer than rod $A$ by
A) $(0.94\ \pm 0.00)\ cm$
B) $(0.94\ \pm 0.01)\ cm$
C) $(0.94\ \pm 0.02)\ cm$
D) $(0.94\ \pm 0.005)\ cm$
Explanation
Given, length of rod $A$ is $L_{A} = 3.25 \pm 0.01$ Of B is $L_{B} = 4.19 \pm 0.01$ Then, the rod B is longer than rod A by a length $\mathrm{\Delta}l = L_{B} - L_{A}$ $\mathrm{\Delta}l = (4.19 \pm 0.01) - (3.25 \pm 0.01)$ $\mathrm{\Delta}l = (0.94 \pm 0.02)cm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.