Q. The value of universal gas constant is $R = 8.3$ J/K-mol. The value of $R$ in atmosphere litre per Kelvin mol
A) 8.12
B) 0.00812
C) 81.2
D) 0.0812
Explanation
R=8.3 J/K-mol $n_{1}u_{1} = n_{2}u_{2}$ $\therefore\ \ n_{2} = \frac{n_{1}u_{1}}{u_{2}}$ $= \frac{8.3J/K - mol}{atm\ L/K - mol}$ $= \frac{8.3J/K - mol}{\left( 1.013 \times 10^{5}N{/m}^{2} \right)\left( 10^{- 3}m^{3} \right)/K - mol}$ $= \frac{8.12}{10^{2}} = 0.0812$ $\therefore 8.3\$J/K-mol=0.0812 atm L/K-mol
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.