Q. The equation $\left( P + \frac{a}{V^{2}} \right)$. $(V\ - \ b) =$ constant. The unit of $a$ is
A) $Dyne\ \times \ cm^{5}$
B) $Dyne\ \times \ {cm}^{4}$
C) $Dyne\ \times \ cm^{3}$
D) $Dyne\ \times \ cm^{2}$
Explanation
Units of $a\$and $PV^{2}$ are same and equal to $dyne\ \times cm^{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.