Note carefully that every alterative has $Gh$ and $c^{5}$. $\lbrack Gh\rbrack = \left\lbrack M^{- 1}L^{3}T^{- 2} \right\rbrack\left\lbrack ML^{2}T^{- 1} \right\rbrack = \lbrack M^{0}L^{5}T^{3}\rbrack$ $\lbrack c\rbrack = \lbrack LT^{- 1}\rbrack$ $\therefore\ \ \ \ \ \left( \frac{Gh}{c^{5}} \right)^{1/2} = \lbrack T\rbrack$