Q. Dimensions of ohm are same as ($h -$Planck’s constant, $e -$charge)
A) $h/e$
B) $h^{2}/e$
C) $h/e^{2}$
D) $h^{2}e^{2}$
Explanation
Dimensional formula of $ohm = \lbrack ML^{2}T^{- 3}A^{- 2\ }\rbrack$ and that of $\frac{h}{e^{2}} = \frac{\left\lbrack ML^{2}T^{- 1}\ \right\rbrack}{A^{2}T^{2}} = \lbrack ML^{2}T^{- 3}A^{- 2}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.