Q. The surface tension of a liquid is $70\ dyne/cm$, in $MKS$ system value is
A) $70\ N/m$
B) $7 \times 10^{- 2}\ N/m$
C) $7 \times 10^{3}\ N/m$
D) $7 \times 10^{2}\ N/m$
Explanation
$1\ dyne = 10^{- 5}\ newton,\ 1\ cm = 10^{- 2}\ m$ $70\frac{dyne}{cm} = \frac{70 \times 10^{- 5}}{10^{- 2}}\frac{N}{m}$ $= 7 \times 10^{- 2}N/m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.