Q. A population is in Hardy-Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele’A’ is 0.7, genotype frequency of ‘a’ is

A) 0.21
B) 0.42
C) 0.36
D) 0.7
Explanation

According to Hardy-Weinberg law, at equilibrium, genetic and allelic frequencies remain constant from one generation to next generation. It can be mathematically expressed as For allelic frequency A+a=1 For genetic frequency $A^{2} + a^{2} + 2Aa = 1$ So, allelic frequency of A=0.7 So, allelic frequency of a=1$-$0.7=0.3 Therefore, the genetic frequency of Aa is =2(Aa) $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 2(0.7 \times 0.3)$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 2 \times 0.21 = 0.42$ So, frequency of Aa=0.42.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Evolution MCQs