Q. A suitable unit for gravitational constant is
A) $kg$-$m\ \sec^{- 1}$
B) $N\ m^{- 1}\sec$
C) $N\ m^{2}\ kg^{- 2}$
D) $kg\ m\ \sec^{- 1}$
Explanation
$F = \frac{Gm_{1}m_{2}}{d^{2}};\ \ \therefore\ G = \frac{Fd^{2}}{m_{1}m_{2}} = Nm^{2}/kg^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.