Q. If frequency, of ‘A’ allele is 0.4 than, find out the frequency of ‘B’ allele and heterozygous genotype in a random mating population at equilibria
A) 0.6 and 0.24
B) 0.6 and 0.96
C) 0.6 and 0.48
D) 0.6 and 0.50
Explanation
HW Principle = p + q =1 $p^{2} + 2pq + q^{2} = 1$ Here, p = A and q is = B Allele frequency of B = 1-0.4 = 0.6 Allele frequency of heterozygous is = $2 \times 0.6 \times 0.4$ $= 0.48$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.