Q. The dimensions of Planck’s constant are
A) $\left\lbrack M^{2}L^{2}T^{- 2} \right\rbrack$
B) $\left\lbrack {MLT}^{- 2} \right\rbrack$
C) $\left\lbrack {ML}^{2}T^{- 2} \right\rbrack$
D) $\left\lbrack {ML}^{2}T^{- 1} \right\rbrack$
Explanation
According to Planck’s hypothesis $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ E = hv$ Or $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ h = \frac{E}{v}$ Substituting the dimensions of energy $E$ and frequency$\ v,$ we get $\lbrack h\rbrack = \frac{\left\lbrack {ML}^{2}T^{- 2} \right\rbrack}{\left\lbrack T^{- 1} \right\rbrack}$ $\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \lbrack h\rbrack = \left\lbrack ML^{2}T^{- 1} \right\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.