A physical quantity $u$ is given by the relation $u = \frac{B^{2}}{2\mu_{0}}$ here, $B =$magnetic field strength $\mu_{0} =$magnetic permeability of vacuum.

Question

Dr. Abubacker · Accepted Answer

Physical quantity $u = \frac{B^{2}}{2\mu_{0}}$ Unit of $u = \frac{(N/Am)^{2}}{N/A^{2}} = \frac{N^{2}A^{2}}{NA^{2}m^{2}}$ $= \frac{N}{m^{2}} = \frac{Nm}{m^{3}} = \frac{J}{m^{3}}$ $=$ energy per unit volume = energy density

Q. A physical quantity $u$ is given by the relation $u = \frac{B^{2}}{2\mu_{0}}$ here, $B =$magnetic field strength $\mu_{0} =$magnetic permeability of vacuum.

Explanation

Reviewed by Dr. Abubacker

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