Q. The unit of potential energy is
A) $g(cm/\sec^{2})$
B) $g\left( cm/\sec \right)^{2}$
C) $g(cm^{2}/\sec)$
D) $g(cm/\sec)$
Explanation
$Potential\ energy = mgh = g\left( \frac{cm}{\sec^{2}\ } \right)cm = g\left( \frac{cm}{\sec} \right)^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.