Q. A student performs an experiment for determination of $g = \frac{4\pi^{2}l}{T^{2}}$ and he commits an error of $\ \mathrm{\Delta}l$. For that he takes the time of $n$ oscillations with the stop watch of least count $\mathrm{\Delta}T$ and he commits a human error of $\ 0.1\ sec$. For which of the following data, the measurement of $g$ will be most accurate $\mathrm{\Delta}l$ $\mathrm{\Delta}T$ $n$ Ampli. of oscill.
A) $5\ mm$ $0.2sec$ $10$ $5mm$
B) $5\ mm$ $0.2sec$ $20$ $5mm$
C) $5\ mm$ $0.1sec$ $20$ $1mm$
D) $1\ mm$ $0.1sec$ $50$ $1mm$
Explanation
For best results amplitude of oscillation should be as small as possible and more oscillations should be taken
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.