What is the unit of $k$ in the relation $U = \frac{ky}{y^{2} + a^{2}}$ where $U$ represents the potential energy, $y$ represents the displacement and $a$ represents the maximum displacement $ie$, amplitude?

Question

Dr. Abubacker · Accepted Answer

The right hand side of the given relation is basically $\frac{k}{metre}.$ But, since the left hand side is joule, therefore $k$ should be J m.

Q. What is the unit of $k$ in the relation $U = \frac{ky}{y^{2} + a^{2}}$ where $U$ represents the potential energy, $y$ represents the displacement and $a$ represents the maximum displacement $ie$, amplitude?

Explanation

Reviewed by Dr. Abubacker

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