Q. If $C\$and $L$ denote capacitance and inductance respectively, then the dimensions of $LC$ are
A) $M^{0}L^{0}T^{0}$
B) $M^{0}L^{0}\ T^{2}$
C) $M^{2}L^{0}T^{2}$
D) $MLT^{2}$
Explanation
$f = \frac{1}{2\pi\sqrt{LC}} \Rightarrow LC = \frac{1}{f^{2}} = \lbrack M^{0}L^{0}T^{2}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.