Q. If $E,\ M,\ L$ and $G$ denote energy, mass, angular momentum and gravitational constant respectively, then the quantity $(EL^{2}/M^{5}G^{2})$ has the dimensions of

A) Angle
B) Length
C) Mass
D) Time
Explanation

$\lbrack E\rbrack = \left\lbrack ML^{2}T^{- 2} \right\rbrack$ $\lbrack M\rbrack = \lbrack M\rbrack$ $\lbrack L\rbrack = \left\lbrack ML^{2}T^{- 1} \right\rbrack$ $\lbrack G\rbrack = \left\lbrack M^{- 1}L^{3}T^{- 2} \right\rbrack$ $\left\lbrack \frac{EL^{2}}{M^{5}G^{2}} \right\rbrack = \frac{\left\lbrack ML^{2}T^{- 2} \right\rbrack\left\lbrack ML^{2}T^{- 1} \right\rbrack^{2}}{\lbrack M\rbrack^{5}\left\lbrack M^{- 1}L^{3}T^{- 2} \right\rbrack^{2}}$ $= \frac{\left\lbrack ML^{2}T^{- 2} \right\rbrack\lbrack M^{2}L^{4}T^{- 2}\rbrack}{\left\lbrack M^{5} \right\rbrack\lbrack M^{- 2}L^{6}T^{- 4}\rbrack} = \frac{\lbrack M^{3}L^{6}T^{- 4}\rbrack}{{\lbrack M}^{3}L^{6}T^{- 4}\rbrack}$ $= \left\lbrack m^{0}L^{0}T^{0} \right\rbrack =$ Angle

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.