A physical quantity $P\$is given by $P = \frac{A^{3}B^{\frac{1}{\ 2}}}{C^{- 4}D^{\frac{3}{2}}}.$ The quantity which brings in the maximum percentage error in $P$ is

Question

Dr. Abubacker · Accepted Answer

Quantity $C$ has maximum power. So it brings maximum error in $P$

Q. A physical quantity $P\$is given by $P = \frac{A^{3}B^{\frac{1}{\ 2}}}{C^{- 4}D^{\frac{3}{2}}}.$ The quantity which brings in the maximum percentage error in $P$ is

Explanation

Reviewed by Dr. Abubacker

Want more practice?