Q. Find out $dN/dt$, when carrying capacity is 400, population size is 300 and $r$ is = 0.01
A) 0.01
B) 0.8
C) 0.75
D) 0.45
Explanation
$\frac{dN}{dt} = rN\left( \frac{K - N}{K} \right)$ $\frac{dN}{dt} = 0.01 \times 300\left( \frac{400 - 300}{400} \right)$ $\frac{dN}{dt} = 3 \times \left( \frac{100}{400} \right)$ $\frac{dN}{dt} = \frac{3}{4}$ $\frac{dN}{dt} = 0.75$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.