Q. Mr. Sidd is suffering from hypertrichosis and phenylketonuria. His father is heterozygous for phenylketonuria. The probability of Sidd’s sperm having one recessive autosomal allele and holandric gene is
A) $\frac{1}{2}$
B) $\frac{1}{8}$
C) $\frac{1}{10}$
D) $\frac{1}{4}$
Explanation
In the gametogenesis meiosis occur. The diploid chromosome become haploid, so the probability of side is sperm lacking one recessive autosomal allele and holandric gene is half
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.