(c) For shortest possible path man should swim with an angle $(90 + \theta)$ with downstream
From the fig,
$\sin\theta = \frac{v_{r}}{v_{m}} = \frac{5}{10} = \frac{1}{2}$
$\Rightarrow \ \therefore\ \theta = 30{^\circ}$
So angle with downstream $= 90{^\circ} + 30{^\circ} = 120{^\circ}$