Q. A stone is allowed to fall from the top of a tower 100m high and at the same time another stone is projected vertically upwards from the ground with a velocity of $254ms^{- 1}$. The two stones will meet after
A) 4 s
B) 0.4 s
C) 0.04 s
D) 40 s
Explanation
(a) $x = \frac{1}{2}gt^{2},100 - x = 25x - \frac{1}{2}gt^{2};$
Adding 25$t = 100$ or $t = 4$ s
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.