Q. When a ball is thrown up vertically with velocity $V_{0}$ , it reaches a maximum height of $'h'$. If one wishes to triple the maximum height then the ball should be thrown with velocity
A) $\sqrt{3}V_{0}$
B) $3V_{0}$
C) $9V_{0}$
D) $3/2V_{0}$
Explanation
(a) $H_{\max} \propto u^{2}\therefore u \propto \sqrt{H_{\max}}$
$i.e.\ $to triple the maximum height, ball should be thrown with velocity $\sqrt{3}\ u$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.