Q. A car starts from rest and accelerates uniformly to a speed of $180\ kmh^{- 1}$ in $10\ seconds$. The distance covered by the car in this time interval is
A) $500\ m$
B) $250\ m$
C) $100\ m$
D) $200\ m$
Explanation
(b) $u = 0,\ v = 180\ km\ h^{- 1} = 50\ ms^{- 1}$
Time taken $t = 10s$
$a = \frac{v - u}{t} = \frac{50}{10} = 5\ ms^{- 2}$
$\therefore$ Distance covered $S = ut + \frac{1}{2}at^{2}$
$= 0 + \frac{1}{2} \times 5 \times (10)^{2} = \frac{500}{2} = 250\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.