Q. A body is moving according to the equation $x = at + bt^{2} - ct^{3}$ where $x =$ displacement and $a,\ b$ and $c$ are constants. The acceleration of the body is
A) $a + 2bt$
B) $2b + 6ct$
C) $2b - 6ct$
D) $3b - 6ct^{2}$
Explanation
(c) $x = at + bt^{2} - ct^{3},\ a = \frac{d^{2}x}{dt^{2}} = 2b - 6ct$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.