Q. The distance travelled by a particle is proportional to the square of time, then the particle travels with
A) Uniform acceleration
B) Uniform velocity
C) Increasing acceleration
D) Decreasing velocity
Explanation
(a) $s \propto t^{2}\lbrack Given\rbrack\therefore s = Kt^{2}$
Acceleration $a = \frac{d^{2}s}{dt^{2}} = 2k$ [constant]
It means the particle travels with uniform acceleration
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.