Q. A packet is dropped from a balloon which is going upwards with the velocity $12\ m/s$ , the velocity of the packet after 2 seconds will be
A) $- 12\ m/s$
B) $12\ m/s$
C) $- 7.6\ m/s$
D) $7.6\ m/s$
Explanation
(c) When packet is released from the balloon, it acquires the velocity of balloon of value $12\ m/s$. Hence velocity of packet after $2\ sec$, will be
$v = u + gt = 12 - 9.8 \times 2 = - 76\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.