Q. Two balls are dropped from height $h$ and $2h$ respectively from the earth surface. The ratio of time of these balls to reach the earth is
A) $1\ :\ \sqrt{2}$
B) $\sqrt{2}\ :1$
C) $2\ :1$
D) $1\ :4$
Explanation
(a) $t = \sqrt{\frac{2h}{g}} \Rightarrow \frac{t_{1}}{t_{2}} = \sqrt{\frac{h_{1}}{h_{2}}} = \sqrt{\frac{1}{2}} = \frac{1}{\sqrt{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.