Starting from rest, acceleration of a particle is $a = 2(t - 1)$. The velocity of the particle at $t = 5s$ is

Question

Dr. Abubacker · Accepted Answer

(a) $\because a = \frac{dv}{dt} = 2(t - 1) \Rightarrow dv = 2(t - 1)dt$
$\Rightarrow v = \int_{0}^{5}{2(t - 1)dt = 2}\left\lbrack \frac{t^{2}}{2} - t \right\rbrack_{0}^{5} = 2\left\lbrack \frac{25}{2} - 5 \right\rbrack\  = 15\ m/s$

Q. Starting from rest, acceleration of a particle is $a = 2(t - 1)$. The velocity of the particle at $t = 5s$ is

Explanation

Reviewed by Dr. Abubacker

Want more practice?