Q. A body $A\ $starts from rest with an acceleration $a_{1}.$ After 2 seconds, another body $B\ $starts from rest with an acceleration $a_{2}.$ If they travel equal distances in the 5th second, after the start of A, then the ration $a_{1}:a_{2}$ is equal to

A) $5\ :9$
B) $5\ :7$
C) $9\ :5$
D) $9\ :7$
Explanation

(a) According to problem
Distance travelled by body $A$ in $5^{th}\ sec$ and distance travelled by body $B$ in $3^{rd}\ sec$. of its motion are equal.
$0 + \frac{a_{1}}{2}(2 \times 5 - 1) = 0 + \frac{a_{2}}{2}\lbrack 2 \times 3 - 1\rbrack$
$9a_{1} = 5a_{2} \Rightarrow \frac{a_{1}}{a_{2}} = \frac{5}{9}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.