An elevator car, whose floor to ceiling distance is equal to 2.7$m,$ starts ascending with constant acceleration of $1.2ms^{- 2}.$ 2 $\sec$ after the start, a bolt begins falling from the ceiling of the car. The free fall time of the bolt is

Question

Dr. Abubacker · Accepted Answer

(c) $t = \sqrt{\frac{2h}{(g + a)}} = \sqrt{\frac{2 	imes 2.7}{(9.8 + 1.2)}} = \sqrt{\frac{5.4}{11}} = \sqrt{0.49} = 0.7\ \sec$
As $u = 0$ and lift is moving upward with acceleration

Q. An elevator car, whose floor to ceiling distance is equal to 2.7$m,$ starts ascending with constant acceleration of $1.2ms^{- 2}.$ 2 $\sec$ after the start, a bolt begins falling from the ceiling of the car. The free fall time of the bolt is

Explanation

Reviewed by Dr. Abubacker

Want more practice?