Q. A particle has an initial velocity $3\widehat{\mathbf{i}} + 4\widehat{\mathbf{j}}\mathbf{\ }$and an acceleration of $\ 0.4\widehat{\mathbf{i}}\mathbf{+}0.3\widehat{\mathbf{j}}\mathbf{.\ }$Its speed after 10 s is

A) 10 unit
B) 7 unit
C) $7\sqrt{2}unit$
D) 8.5 unit
Explanation

(c) $\mathbf{u} = 3\widehat{\mathbf{i}} + 4\widehat{\mathbf{j}},\mathbf{\ a} = 0.4\widehat{\mathbf{i}} + 0.3\widehat{\mathbf{j}}$
Speed $\mathbf{v} = \mathbf{u} + \mathbf{a}t$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 3\widehat{\mathbf{i}} + 4\widehat{\mathbf{j}} + \left( 0.4\widehat{\mathbf{i}} + 0.3\widehat{\mathbf{j}} \right)10$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 3\widehat{\mathbf{i}} + 4\widehat{\mathbf{j}} + 4\widehat{\mathbf{i}} + 3\widehat{\mathbf{j}} = 7\widehat{\mathbf{i}} + 7\widehat{\mathbf{j}}$
$\ \ \ \ \ \ \ \ \ \ \ v = \sqrt{7^{2} + 7^{2}} = 7\sqrt{2}\ unit$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.