Q. A particle is moving with constant acceleration from $A\ \ to\ B$ in a straight line $AB.$ If $u\ and\ v$ are the velocities at $A\ and\ B$ respectively, then its velocity at the midpoint $c$ will be
A) $\left( \frac{u^{2} + v^{2}}{2u} \right)^{2}$
B) $\frac{u + v}{2}$
C) $\frac{v - u}{2}$
D) $\sqrt{\frac{u^{2} + v^{2}}{2}}$
Explanation
(d) We have standard result for this type of velocity
$v = \sqrt{\frac{u^{2} + v^{2}}{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.