(b) (i) $\frac{\frac{1}{2} \times OA \times AC}{OA} + \frac{\frac{1}{2} \times AB \times AC}{AB} = 1$
(ii) tan60${^\circ}$=$\frac{CA}{OA}$ and tan30${^\circ}$=$\frac{CA}{AB}$
$OA$ tan60${^\circ}$=$AB\ $tan $30{^\circ}$
or $\frac{OA}{AB} = \frac{tan30{^\circ}}{tan60{^\circ}} = \frac{1}{\sqrt{3}} \times \frac{1}{\sqrt{3}} = \frac{1}{3}$