(a) Here, $u = 0,\ a = g$ Distance travelled in $n^{th}$ second is given by $D_{n} = u + \frac{a}{2}(2n - 1)\ \therefore D_{n} \propto (2n - 1)$ $\therefore D_{1}:D_{2}:D_{3}\ :D_{4}\ :D_{5}\ldots = 1\ :3\ :5\ :7\ :9\ :\ldots$
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