A bus begins to move with an acceleration of $1ms^{- 2}$. A man who is $48m$ behind the bus starts running at $10\ ms^{- 1}$ to catch the bus. The man will be able to catch the bus after

Question

Dr. Abubacker · Accepted Answer

(d) Let the man will be able to catch the bus after $t\ s$
Then
$10t = 48 + \frac{1}{2} 	imes 1 	imes t^{2}$
$t^{2} - 20t + 96 = 0$
$(t - 12)(t - 8) = 0$
$t = 8s$ and $t = 12s$
Thus the man will be able to catch the bus after $8s$

Q. A bus begins to move with an acceleration of $1ms^{- 2}$. A man who is $48m$ behind the bus starts running at $10\ ms^{- 1}$ to catch the bus. The man will be able to catch the bus after

Explanation

Reviewed by Dr. Abubacker

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