Q. The distance between two particles moving towards each other is decreasing at the rate of $6m/sec$. If these particles travel with same speeds and in the same direction, then the separation increase at the rate of $4m/sec$. The particles have speeds as
A) $5m/sec$ $:1m/sec$
B) 4 $m/sec$ $:$ $1m/sec$
C) 4 $m/sec$ $:2m/sec$
D) $5\ m/sec$ $:2m/sec$
Explanation
(a) When two particles moves towards each other then
$v_{1} - v_{2} = 6$ …(i)
When these particles moves in the same direction then
$v_{1} - v_{2} = 4$ …(ii)
By solving $v_{1} = 5$ and $v_{2} = 1\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.