Q. A ball is thrown vertically upwards from the surface of earth with a speed of 18$kmh^{- 1}$. If $g = 10ms^{- 2}$, then the maximum height attained by the ball is
A) 1.25 m
B) 3 m
C) 10 m
D) 180 m
Explanation
(a) $v = 18 \times \frac{5}{18}ms^{- 1} = 5ms^{- 1},$
$h_{\max} = \frac{5 \times 5}{2 \times 10}$m =$\frac{25}{20}$m =1.25m
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.