Q. A man throws a ball vertically upward and it rises through $20\ m$ and returns to his hands. What was the initial velocity ($u$) of the ball and for how much time ($T$) it remained in the air $\lbrack g = 10m/s^{2}\rbrack$

A) $u = 10m/s$,$T = 2s$
B) $u = 10m/s$,$T = 4s$
C) $u = 20m/s$,$T = 2s$
D) $u = 20m/s$,$T = 4s$
Explanation

(d) $u = \sqrt{2gh} = \sqrt{2 \times 10 \times 20} = 20m/s$
and $T = \frac{2u}{g} = \frac{2 \times 20}{10} = 4\ sec$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.