A particle starts its motion from rest under the action of a constant force. If the distance covered in first $10\ seconds\ $ is $S_{1}$ and that covered in the first $20\ seconds$ is $S_{2}$, then

Question

Dr. Abubacker · Accepted Answer

(c) $S \propto t^{2} \Rightarrow \frac{S_{1}}{S_{2}} = \left( \frac{10}{20} \right)^{2} \Rightarrow S_{2} = 4S_{1}$

Q. A particle starts its motion from rest under the action of a constant force. If the distance covered in first $10\ seconds\ $ is $S_{1}$ and that covered in the first $20\ seconds$ is $S_{2}$, then

Explanation

Reviewed by Dr. Abubacker

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