The displacement of a particle undergoing rectilinear motion along the $x$-axis is given by $x = (2t^{2} + 21t^{2} + 60t + 6)$. The acceleration of the particle when its velocity is zero is

Question

Dr. Abubacker · Accepted Answer

(d) $x = 2t^{3} + 21t^{2} + 60t + 6$
$	herefore v = \frac{dx}{dt} = 6t^{2} + 42t + 60$
But , $v = 0$ (given)
$t^{2} + 7t + 10 = 0$
$\Rightarrow \ \ t = - 5$s
or $t = - 2$s
$a = \frac{dv}{dt} = 12t + 42$
$a\ \left. \  ight|_{t = 5s} = - 60 + 42 = - 18ms^{- 2}$
$a\ \left. \  ight|_{t = - 2s} = - 24 + 42 = 18ms^{- 2}$

Q. The displacement of a particle undergoing rectilinear motion along the $x$-axis is given by $x = (2t^{2} + 21t^{2} + 60t + 6)$. The acceleration of the particle when its velocity is zero is

Explanation

Reviewed by Dr. Abubacker

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