Q. A stone falls from a balloon that is descending at a uniform rate of $12ms^{- 1}$. The displacement of the stone from the point of release after 10s is
A) 725 m
B) 610 m
C) 510 m
D) 490 m
Explanation
(b) $u = 12ms^{- 1},g = 9.8ms^{- 2},t = 10s$
$S = \left( 12 \times 10 + \frac{1}{2} \times 9.8 \times 10 \times 10 \right)$m
$= (120 + 4.9 \times 100)$m=610m
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.