Q. A body of mass $m$ moving along a straight line covers half the distance with a speed of $2{ms}^{- 1}.$ The remaining half of distance is covered in two equal time intervals with a speed of $3\ {ms}^{- 1}and\ \ 5\ {ms}^{- 1}$ respectively. The average speed of the particle for the entire journey is

A) $\frac{3}{8}{ms}^{- 1}$
B) $\frac{8}{3}{ms}^{- 1}$
C) $\frac{4}{3}{ms}^{- 1}$
D) $\frac{16}{3}{ms}^{- 1}$
Explanation

(b) Let the total distance travelled by the body is $2S.$ If $t_{1}$ is the time taken by the body to travel first half of the distance, then
${\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ t}_{1} = \frac{S}{2}$
Let $t_{2}$ be the time taken by the body for each time interval for the remaining half journey.
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ S = 3t_{2} + 5t_{2} = 8t_{2}$
$So,\ average\ speed\ = \frac{Total\ distance\ travelled}{Total\ time\ taken}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{2S}{t_{1} + 2t_{2}} = \frac{2S}{\frac{S}{2} + \frac{S}{4}} = \frac{8}{3}{ms}^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.