Q. If the velocity of a particle is $\left( 10 + 2t^{2} \right)m/s$, then the average acceleration of the particle between $2s$ and $5s$ is
A) $2m/s^{2}$
B) $4m/s^{2}$
C) $12m/s^{2}$
D) $14m/s^{2}$
Explanation
(d) Average acceleration = $\frac{Change\ in\ velocity}{Time\ taken\ } = \frac{v_{2} - v_{1}}{t_{2} - t_{1}}$
$= \frac{\left\lbrack 10 + 2(5)^{2} \right\rbrack - \left\lbrack 10 + 2(2)^{2} \right\rbrack}{3} = \frac{60 - 18}{3}14m/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.