The relation $3t = \sqrt{3x} + 6$ describes the displacement of a particle in one direction where $x\ $is in $metres$ and $t$ in sec. The displacement, when velocity is zero, is

Question

Dr. Abubacker · Accepted Answer

(d) $3t = \sqrt{3x} + 6 \Rightarrow 3x = (3t - 6)^{2}$
$\Rightarrow x = 3t^{2} - 12t$+12
$v = \frac{dx}{dt} = 6t - 12,\ $for $v = 0,t = 2\ \sec$
$x = 3(2)^{2} - 12 	imes 2 + 12 = 0$

Q. The relation $3t = \sqrt{3x} + 6$ describes the displacement of a particle in one direction where $x\ $is in $metres$ and $t$ in sec. The displacement, when velocity is zero, is

Explanation

Reviewed by Dr. Abubacker

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