A juggler keeps on moving four balls in the air throws the balls in regular interval of time. When one ball leaves his hand (speed=$20ms^{- 1}$), the position of other ball will be (Take $g = 10ms^{- 2}$)

Question

Dr. Abubacker · Accepted Answer

(c) [image:3_image168.emf]
$h_{1} = \frac{1}{2}gt^{2} = \frac{1}{2} 	imes 10 	imes 1^{2} = 5$m
$h_{2} = \frac{1}{2}gt^{2} = \frac{1}{2} 	imes 10 	imes 2^{2} =$20m
From ground, 5m, 20m, 15m (shown in figure)

Q. A juggler keeps on moving four balls in the air throws the balls in regular interval of time. When one ball leaves his hand (speed=$20ms^{- 1}$), the position of other ball will be (Take $g = 10ms^{- 2}$)

Explanation

Reviewed by Dr. Abubacker

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