The displacement of a particle is given by $y = a + bt + ct^{2} - dt^{4}$. The initial velocity and acceleration are respectively

Question

Dr. Abubacker · Accepted Answer

(c) $y = a + bt + ct^{2} - dt^{4}$
$	herefore v = \frac{dy}{dt} = b + 2ct - 4dt^{3}$ and $a = \frac{dv}{dt} = 2c - 12dt^{2}$
Hence, at $t = 0,\ v_{initial} = b$ and $a_{initial} = 2c$

Q. The displacement of a particle is given by $y = a + bt + ct^{2} - dt^{4}$. The initial velocity and acceleration are respectively

Explanation

Reviewed by Dr. Abubacker

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