(a) $\mathbf{r} = x\widehat{\mathbf{i}} + y\widehat{\mathbf{j}} + z\widehat{\mathbf{k}}$ $\therefore\mathbf{r} = \sqrt{x^{2} + y^{2} + z^{2}}$ $\mathbf{r} = \sqrt{6^{2} + 8^{2} + 10^{2}} = 10\sqrt{2}m$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.