Q. A bullet comes out of the barrel of gun of length 2m with a speed $80\ {ms}^{- 1}.$ The average acceleration of the bullet is
A) $1.6\ {ms}^{- 2}$
B) $160\ {ms}^{- 2}$
C) $1600\ {ms}^{- 2}$
D) $16\ {ms}^{- 2}$
Explanation
(c) Given, $s = 2\ m,\ u = 80\ {ms}^{- 1},\ v = 0$
From $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v^{2} = u^{2} - 2as$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (0)^{2} = (80)^{2} - 2 \times a \times 2$
Or $a = \frac{80\ \times 80}{4} = 1600\ {ms}^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.