A bus begins to move with an acceleration of $1\ {ms}^{- 2}.$ A man who is 48 m behind the bus starts running at $10\ {ms}^{- 1}$ to catch the bus. The man will be able to catch the bus after

Question

Dr. Abubacker · Accepted Answer

(d) Given, $a = 1\ m/s,\ s = 48\ m$
By equation of motion
$\ \ \ \ \ \ \ \ \ \ \ 48 = 10t + \frac{1}{2}at^{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ t = 8\ s$

Q. A bus begins to move with an acceleration of $1\ {ms}^{- 2}.$ A man who is 48 m behind the bus starts running at $10\ {ms}^{- 1}$ to catch the bus. The man will be able to catch the bus after

Explanation

Reviewed by Dr. Abubacker

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