Two bodies of different masses $m_{a}\ $and $m_{b}$ are dropped from two different heights $a$ and $b$. The ratio of the time taken by the two to cover these distances are

Question

Dr. Abubacker · Accepted Answer

(c) $h = \frac{1}{2}gt^{2} \Rightarrow t = \sqrt{2h/g}$
$t_{a} = \sqrt{\frac{2a}{g}}$ and $t_{b} = \sqrt{\frac{2b}{g}} \Rightarrow \frac{t_{a}}{t_{b}} = \sqrt{\frac{a}{b}}$

Q. Two bodies of different masses $m_{a}\ $and $m_{b}$ are dropped from two different heights $a$ and $b$. The ratio of the time taken by the two to cover these distances are

Explanation

Reviewed by Dr. Abubacker

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